2x/x+4-8/x-4=2x^2+32/x^2-16

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Solution for 2x/x+4-8/x-4=2x^2+32/x^2-16 equation: 



2x/x+4-8/x-4=2x^2+32/x^2-16

We move all terms to the left:

2x/x+4-8/x-4-(2x^2+32/x^2-16)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2-16)!=0

x∈R



We add all the numbers together, and all the variables

2x/x-8/x-(2x^2+32/x^2-16)=0

We get rid of parentheses

-2x^2+2x/x-8/x-32/x^2+16=0

We calculate fractions

We do not support expression: x^3

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